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fahur · #1 (**permalink**) 03-16-2007, 01:52 PM

Hi!

I have a problem with variables scope.

Firstly, a little code...

There's a loop in the loop:

Code:

echo `gsh list_eq all > $TEMP`

while read line
do
  SHELF=`echo $line | awk '{ print $1 }'`
  SLOT=`echo $line | awk '{ print $2 }'`
  echo `gsh get_eq_info -eq { $SHELF $SLOT } > $TEMP1`
  egrep "ProdName|ProdNo|Revision|SerialNo" $TEMP1 > $TEMP2
  while read line
  do
    PAR=`echo $line | awk '{ print $1 }'`
    VAL=`echo $line | awk '{ print $3 $4 $5 }'`
    if [ "$PAR" = "ProdName" ]; then
      PRODNAME=$VAL
      echo $PRODNAME
    elif [ "$PAR" = "ProdNo" ]; then
      PRODNO=$VAL
      echo $PRODNO
    elif [ "$PAR" = "Revision" ]; then
      REV=$VAL
      echo $REV
    else
      SERIALNO=$VAL
      echo $SERIALNO
    fi
  done < $TEMP2
  echo "$SHELF $SLOT;$PRODNAME;$PRODNO;$REV;$SERIALNO;"
done < $TEMP

Everything's OK, but when I try to display all parameters in the end (finally it will by written to the CSV file):

Code:

echo "$SHELF $SLOT;$PRODNAME;$PRODNO;$REV;$SERIALNO;"

I only see sth like this:

Code:

1 1;;;;;

So it's simple - all the parameters in the internal loop are not "viewable" (empty) outside. I echoed them inside and they are not empty.

The problem is I have to place all the params in one line, because (as mentioned above), I need them in CSV file. When I write them directly to the file, every param is placed in next line and this is not an option.

Does anyone has an idea?!

Thanks is advanced...

--
Rgds
fahur

tom · #2 (**permalink**) 03-16-2007, 04:25 PM

initialize variables before starting while loop

Code:

SHELF=""
SLOT=""
PRODNAME=""
PRODNO=""
REV=""
SERIALNO=""
# start while loop
,,,,
,.....
..

If problem continues debug line

Code:

VAL=`echo $line | awk '{ print $3 $4 $5 }'`

Run script as

Code:

bash -x  ./script-name

fahur · #3 (**permalink**) 03-16-2007, 06:38 PM

Quote:

Originally Posted by tom

initialize variables before starting while loop

Code:

SHELF=""
SLOT=""
PRODNAME=""
PRODNO=""
REV=""
SERIALNO=""
# start while loop
,,,,
,.....
..

Unfortunatelly, doesn't work for me

Quote:

If problem continues debug line

Code:

VAL=`echo $line | awk '{ print $3 $4 $5 }'`

If I was to check if it shows the value - yes it is...

--
Rgds
fahur

allotment · #4 (**permalink**) 04-13-2007, 12:56 PM

Code:

echo "$SHELF $SLOT;$PRODNAME;$PRODNO;$REV;$SERIALNO;"

Just a hunch, try to remove the ;
or use harder quote like ' instead of "
otherwise debug the string comparison in the if

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