nixCraft

mala_un · #1 (**permalink**) 08-15-2006, 03:26 PM

hi all,

i have a problem, i did search around but end up disappointed.

lets say i have 3 scripts script_a, script_b and script_c.
all this script is saved in the same directory
what if i want to call script_a and script_b inside a script_c

i've test this way;

#!/bin/bash
clear
if [ -e filename ]
./script_a
else
./script_b
fi
exit

but then, i cant call the ./script_a and ./script_b.
the error message show that there is unexpected before else.

how am i going to do this?

nixcraft · #2 (**permalink**) 08-15-2006, 04:44 PM

Replace if [ -e filename ] with if [ -e filename ] ; then i.e.

Code:

#!/bin/bash
clear
if [ -e filename ]; then
./script_a
else
./script_b
fi
exit

if command syntax is as follows
if [ ]; then
...
else
...
fi

reynold · #3 (**permalink**) 08-15-2006, 04:57 PM

u r syntax is not corretc, here is what help if command gives me back:

Code:

if COMMANDS; then COMMANDS; [ elif COMMANDS; then COMMANDS; ]... [ else COMMANDS; ] fi

mala_un · #4 (**permalink**) 08-16-2006, 10:26 AM

actually what i want to do is

/bin/bash /home/mylnx/script_a

this is the call function in bash since we cant use
call script_a

thanks anyway guys...

mala_un · #5 (**permalink**) 08-16-2006, 10:51 AM

another problem...

i want user to enter a file name..
then i want to check whether the file is exist or not in home directory..
if exist.. copy to new file..

i wrote this way, but its not working...

#!/bin/bash
echo "Enter filename:"
read filename

cd /home/
if [ -e $filename ]
then
cp $filename /home/script/filename2
else
echo "The file not exist"
fi

the result: unexpected .... before else

monk · #6 (**permalink**) 08-16-2006, 02:35 PM

Quote:

#!/bin/bash
echo "Enter filename:"
read filename

cd /home/
if [ -e $filename ]
then
cp $filename /home/script/filename2
else
echo "The file not exist"
fi

Hmm.. did ya copy and pasted code? copy paste may create a problem for you. Your code seems to perfect to me, i hope dir - /home/script/ does exists

Quote:

/bin/bash /home/mylnx/script_a
this is the call function in bash since we cant use
call script_a

To call bash function from other script you need to write as follows:
script_a code with foo() function

Code:

#!/bin/bash
function foo(){
   echo "I am foo()"
}

Now call this foo from mainscript file as follws:

Code:

#!/bin/bash
source script_a
foo

Command source includes the script_a

mala_un · #7 (**permalink**) 08-16-2006, 04:57 PM

hehe
what a shame... it was my fault..

i should write this way

#!/bin/bash
echo "Enter filename:"
read filename

if [ -e $filename ]
then
cp /home/$filename /home/script/filename2
else
echo "The file not exist"
fi

thanks monk

about calling a function
u really give me an idea, i'm gonna test that..

monk · #8 (**permalink**) 08-16-2006, 06:14 PM

Glad to know you are learning fast ...

mala_un · #9 (**permalink**) 08-17-2006, 08:29 AM

i'm a bit confuse...

if i have something like this,
./var $1 $2 $3 $4 $5 $6 $7 $8 $9

what would it used for actually..

nixcraft · #10 (**permalink**) 08-18-2006, 02:36 AM

./var => script name
$1 $2 $3 $4 $5 $6 $7 $8 $9 => All are command line args passed to this script

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call function in bash

call function in bash

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