nixCraft

I am currently working on a PL file. where i encounter some errors.

I am trying to create a dir if it is not available :
########################

23 FILEPATH = '/trs/wg/'.$ToDate.'/'
24 print "Filepath is $FILEPATH\n";
25 if [ ! -d $FILEPATH ]
26 then
27 mkdir $FILEPATH
28 fi

########################
The error was :
Semicolon seems to be missing at printfile.pl line 25.
Semicolon seems to be missing at printfile.pl line 27.
printfile.pl had compilation errors.

Anyone can help me?

If by PL you mean Perl, then your IF/THEN logic needs to use Perl syntax, not Bash syntax:

23 FILEPATH = '/trs/wg/'.$ToDate.'/';
24 print "Filepath is $FILEPATH\n";
25 if ( ! -d $FILEPATH ){

27 mkdir $FILEPATH;
28 }

...Use parentheses () instead of brackets [] to enclose your condition-test statement. Use curly-braces {} to enclose your conditionally-executed block of logic, instead of the 'then' and 'fi' keywords. It is safer to conclude every statement in Perl with a semicolon, like in C, than to see which ones you can get away without (the last one in a curly-brace-enclosed block ...but does it stay the last one when you're busy editing and debugging?).

There is a curly-free way to express a simple conditional statement by flipping the order of the test and dependent-logic:

mkdir $FILEPATH unless -d $FILEPATH;

...and I use those only for simple lines I can read at a glance. (Notice that I used the 'unless' keyword, which is logically "if !" but more readable.)

fwiw
cr