nixCraft

I have a list of files for creating a package.But before going ahead with package i have to check for the file paths

for eg:after running find command on prompt i get
cd acebill
find . -name CR09041494_final.xls
./promo/data/CR09041494_final.xls

find . -name CR09041495_final.xls
./promo/data/CR09041495_final.xls

find . -name ITC0904216703.sql
./promo/sql/swb/ITC0904216703.sql

find . -name Execution_Instructions_RLSE04222009.doc
./promo/doc/Execution_Instructions_RLSE04222009.doc

After getting the path under acebill i have to create a directory named current with same directory structure as found out from find command for the files.
for eg:
like from above find commands
mkdir -p current/promo/data
mkdir -p current/promo/doc
mkdir -p current/promo/sql/swb

after creation of this directory structure i have to copy these files from their previous directories to their corresponding new location
for eg:
$ cd acebill
$ cp promo/data/CR09041494_final.xls current/promo/data
$ cp promo/data/CR09041495_final.xls current/promo/data
$ cp promo/doc/Execution_Instructions_RLSE04222009.doc current/promo/doc


please suggest me a script which can automate this process for number of a large number of files

Use dirname to get directory names:
/promo/doc
Next, use variable to store it and create a dir:
Use for loop to automate above procedure.

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Vivek Gite
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[QUOTE=nixcraft;18814]Use dirname to get directory names:

There's no need to use an external command:

Code:

file=/promo/doc/Execution_Instructions_RLSE04222009.doc
dirname=${file%/*}