nixCraft

vivekv · #1 (**permalink**) 09-03-2009, 12:33 AM

Hello

I want to get the value of extension_dir from php.ini

grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini

This returns

extension_dir = "/usr/local/lib/php/extensions/no-debug-non-zts-20060613"

I just want

/usr/local/lib/php/extensions/no-debug-non-zts-20060613

only.

My question is

How can I search for that and extract it?
I also need to assign it to a vairable

Thanks

vivekv · #2 (**permalink**) 09-03-2009, 01:10 AM

Code:

#!/bin/bash
for  var1 in `cut -f 2 -d "="  /usr/local/lib/php.ini `
do

   echo $var1
done

This is returning all values, but I want extension_dir only

root · #3 (**permalink**) 09-03-2009, 01:42 PM

Try

Code:

 grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2

vivekv · #4 (**permalink**) 09-03-2009, 01:48 PM

Thank you

root@core2quad2 [~]# grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2
"/usr/local/lib/php/extensions/no-debug-non-zts-20060613"
root@core2quad2 [~]#

It is displaying the correct value.

One more question
How can I assign this value to a variable ?

Code:

PATH=grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2
echo $PATH

wont display the result, but it will just display
grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2

nixcraft · #5 (**permalink**) 09-03-2009, 04:26 PM

Code:

VAR=$(grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2)
echo $VAR
export PATH=$PATH:$VAR
echo $PATH

vivekv · #6 (**permalink**) 10-03-2009, 12:00 AM

Quote:

Originally Posted by nixcraft

Code:

VAR=$(grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2)
echo $VAR
export PATH=$PATH:$VAR
echo $PATH

Thank you

I have one more problem

Code:

VAR=$(grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2)
echo "Extension Folder is "  $VAR
wget www.mysite.com/loaders.zip
unzip loaders.zip
mv * $VAR

But here it gives

mv: target `"/usr/local/lib/php/extensions/no-debug-non-zts-20060613"' is not a directory

I assumge, I need to remove the " " from the starting and ending.

How can I do that ?

vivekv · #7 (**permalink**) 10-03-2009, 12:24 AM

I found this is what I need

VAR=$(grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2)
echo "Extension Folder is "
echo "$VAR" | tr '"' ' '

Just wanted to know, how can I assign the output of the last echo command to another variable ?

nixcraft · #8 (**permalink**) 10-03-2009, 03:18 AM

Quote:

Originally Posted by vivekv

I found this is what I need

VAR=$(grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2)
echo "Extension Folder is "
echo "$VAR" | tr '"' ' '

Just wanted to know, how can I assign the output of the last echo command to another variable ?

Try...

Code:

VAR=$(grep -i /usr/local/lib/php/extensions /usr/local/lib/php.ini | cut -d'=' -f2)
echo "Extension Folder is $VAR"

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