nixCraft

Great website guys! Here is my problem - I've been trying to list all of the files in a bin directory along with their short description. Here is the command sequence I'm entering...

cd /bin
find -name '*' -exec man -f {} \;

Output are lines like this one:
./arch: nothing appropriate.

But the list doesn't contain the descriptions. I think the problem is related to the leading "./". If this is so, how can I modify the command to remove the leading "./" before it is fed to the "man -f" command? (I looked at "cut" and "awk", but they seem to be useful for data within files.)

Please help.

Thank you for a great site!
- LW

I'm a little closer to a solution, but haven't yet figured out how to combine the two commands. Here is what I have so far...

echo './test' | sed -e 's/\.\///'

Output:
test

Now, if I can only properly combine this with the "man -f" in the "find" command (above).

Still a little closer as this command lists all of the filenames that I want...

find -name '*' | sed -e 's/\.\///' | sort

But I just can't pass this output to the "man -f" command so as to list the short descriptions as well.

Argggg!!

Of course, I can simplify it further to be...

ls | sed -e 's/\.\///' | sort

To obtain the same output of filenames, but I'm still stumped as to passing the output to "man -f".

This works well enough...

man -f `ls | sed -e 's/\.\///' | sort`

The back-ticks solved the problem!

Well I'm late to party :P here is simple and clean code:
basename is the command you needed.

__________________
Rocky Jr.
You may have my body & soul, but you will never touch my pride!

If you have knowledge, let others light their candles at it.

Certified to work on HP-UX / Sun Solaris / RedHat

Thanks rockdalinux! That's the ticket!
- LW