nixCraft Linux / UNIX / Shell Scripting Forum - Shell scripting

Syntax error near token unexpected token `

SindhuGururaj — Tue, 21 May 2013 01:45:56 GMT

I am new to scripting and hardly use it and urgently need to finish some build script. The below script works perfectly fine on my mac 10.8.x, but throws an error when executed over any other mac 10.6.x/10.8.x. Please help me resolve this issue.

Thanks.

The script basically is to build projects using Xcode.

#! /bin/sh
XCODEBUILD="/Applications/Xcode.app/Contents/Developer/usr/bin/xcodebuild"

#################################### SubRoutines ################################################## ############
# Utility to print the messages

PrintLog()
{
_Log=$1
echo ###############
echo "$_Log"
echo ###############
}

################################################## ##################

platformBaseDir=`( cd ../.. ; pwd )`
cd $platformBaseDir
PrintLog "platformBaseDir is : $platformBaseDir"

This throws an error -
line 12: Syntax error near token unexpected token `
line 12: `PrintLog.

Why does it not throw any error in my 10.8.x, while it never works on any other 10.6.x/10.8.x?
I have tried using _Log = "$1", shebang is included too. I searched the web and this forum too and could not fix it.

Please help.

Thanks.

ls -l with additional info

MrDude — Wed, 15 May 2013 14:06:58 GMT

Hi.

I want to execute ls -l command from script and then add some extra info (could be /var/test).

Example: -rw-r--r-- 1 operus tdoper 2071143 maj 14 10:19 abc.txt /var/test
-rw-r--r-- 1 operus tdoper 2083145 maj 14 10:19 def.txt /var/test
-rw-r--r-- 1 operus tdoper 2087645 maj 14 10:19 ghi.txt /var/test

Any easy ways to do this? ;)

MrDude

Linux command to show current directory via $PWD or pwd

chinalinix — Tue, 14 May 2013 22:39:37 GMT

Hey,

THis is forcing me to ask a basic and silly question - if both $PWD and pwd point to same location to show current dir on Linux. Which one is recommended? Say
old=`pwd`
OR
old="$PWD"

Are they same speed wise?

Execute a condition if and only if the previous one was successful

sbk785 — Tue, 14 May 2013 17:35:14 GMT

hello

i have a script with two conditions ( two different if conditions) : condition1 checks if a fileA exists and
does unique sorting etc. based on this condition-2 extracts a given column and copies to another file.

is there a way to control the executuion of two conditions .. ie.start condiiton2 if condition1 has
completed successfully else exit from the script.

thanks

[Solved] Awk to rearrange column value on Unix or Linux

ananth_ak — Tue, 14 May 2013 12:18:46 GMT

Hi, I have a couple of lines of text where I need to change the format of the date.

AAN-WE-1212-GONE,2012/02/11 12:00:00,"0.00",ZZZ,AAN1112
SOLD/2TDA/GONE42,2011/01/11 11:53:00,"0.00",ZZZ,AAN1112

The date format is in YYYY/MM/DD, I need it in DD/MM/YYYY

so end result needs to look like this:
AAN-WE-1212-GONE,11/02/2012 12:00:00,"0.00",ZZZ,AAN1112
SOLD/2TDA/GONE42,11/01/2011 11:50:00,"0.00",ZZZ,AAN1112

I've tried with awk with gsub and field seperators but I couldn't pull it off.

Can anyone help with this?

Unix / Linux: Searching in two files

sbk785 — Tue, 14 May 2013 02:11:10 GMT

hi

can someone let me know as how to search for a word/s from file1 in file2 and display the matching lines found from file2.

thanks

in array values are not getting stored properly

ramsavi — Mon, 13 May 2013 06:38:52 GMT

hey,i stored the value of an sql query in an array and then tried to use that
value in while loop. actually my array will have two or more values, then according to the values i have to display result.
but it is not working

Code:



#!/bin/bash -xv





val_1=$( sqlplus -s rte/rted1@rel75d1 << EOF

set heading off

select max(istat_id) from cvt_istats;

exit

EOF

)

echo "val_1: $val_1"





nohup ./cvt -f MediationSources.xml &

sleep 60





declare -a arr

arr=$( sqlplus -s rte/rted1@rel75d1 << EOF

set heading off

select source_id from cvt_istats where istat_id > $val_1;

exit

EOF

)

echo "val_2: $arr"





i=0

len=${#arr[@]}

echo $len





while [ $len -gt $i ]

do

  if [ ${arr[$i]} == 1 ]

  then

    echo "%D% FILE MASK PASS"

  elif [ ${arr[$i]} == 2 ]

  then

    echo "%C% FILE MASK PASS"

  else

   echo "FILE MASK FAIL"

  fi





  i=$(( $i + 1 ))

done

Thanks

Using shell loops in unix for comparing files

sbk785 — Sun, 12 May 2013 03:04:55 GMT

hi,

can someone help me with a loop condition to compare two files (f1 & f2), f1 against f2.. display only the contents from f1 that do not match that of f2.

thanks in advance

Sqlplus shell script to read values in variables

ramsavi — Fri, 10 May 2013 06:13:28 GMT

hey , i am using this piece of code to connect to database and execute query and then storing the result of that query in a value . after that i am again using that value in
other other select statement of mine but it is not working.

Code:

#!/bin/bash -xv

val_1=$( sqlplus -s rte/rted1@rel75d1 << EOF

setting heading off

select max(istat_id) from cvt_istats;

exit

EOF

)

echo "val_1: $val_1"

nohup ./cvt -f MediationSources.xml &

sleep 60

val_2=$( sqlplus -s rte/rted1@rel75d1 << EOF

setting heading off

select source_id from cvt_istats where istat_id > $val_1;

exit

EOF

)

echo "val_2: $val_2"

please help
thanks

Projecteuler Problem 3#

Rahul.Patil — Thu, 09 May 2013 09:09:10 GMT

I have solved projecteuler Problem, I just want feedback and code improvement..

PHP Code:


#!/usr/bin/awk -f
# The prime factors of 13195 are 5, 7, 13 and 29.
# What is the largest prime factor of the number 600851475143 ?

function get_PrimeFactor(n) {
           x=2; # minimual prime
           while ( x<n ) {
                   if ( (n%x) == 0 ) {
                           n = n/x
                        }
                         else { # if n not devisable then increment x+1
                           x++
                        }
                }
          return n
}

BEGIN {

                n = ARGV[1] # input number by user
                print get_PrimeFactor(n)
}

Remove comment script

sam12 — Thu, 09 May 2013 00:48:59 GMT

Hello All,

I'm trying to write a shell script that removes the input (another program) comment and outputs the code only. I came with the command line solution, but I don't know how to put it into a bash program.

Here is the command line solution:

sed -e '1{/^#!/ {p}}; /^[\t\ ]*#/d;/\.*#.*/ {/[\x22\x27].*#.*[\x22\x27]/ !{:regular_loop s/$.*$*[^\]#.*/\1/;t regular_loop}; /[\x22\x27].*#.*[\x22\x27]/ {:special_loop s/$[\x22\x27].*#.*[^\x22\x27]$#.*/\1/;t special_loop}; /\\#/ {:second_special_loop s/$.*\\#.*[^\]$#.*/\1/;t second_special_loop}}' "name of your program"

Please help.
Thanks.

Sendmail with header and footer logo in HTML body

junix88 — Tue, 07 May 2013 17:04:18 GMT

Hello,

I need help with my script that will send email via sendmail
command that will shows both the header and footer logo once the recepient
receive the email (e.g. MS Outlook). When I tested to ran the script it will
successfully send the email BUT UNFORTUNATELY it doesn't displayed the logos as
expected to its proper location. What shows was there's NO logo showed up in the Header location, and
the logo showed up in the Footer location was the header logo
image.

Below are the scripts, thusly:

*** In my sendTest.sh
***

Code:

#!/bin/bash

DIR=/var/images

export MAILTO=""

export SUBJECT="Test sendmail html format with logo both header and footer"

export BODY="/var/www/testcid.html"

export MAILPART=`uuidgen` # ***this will gen mailpart  unique id

export MAILPART_BODY=`uuidgen` # ***this will gen mailpart_body id

export ATTACH="$DIR/headerLOGO.jpg"

export ATTACH1="$DIR/footerLOGO.jpg"

(

echo "To: $MAILTO"

echo "Subject: $SUBJECT"

echo "MIME-Version: 1.0"

echo "Content-Type: multipart/mixed; boundary=\"$MAILPART\""

echo ""

echo "--$MAILPART"

echo "Content-Type: multipart/alternative; boundary=\"$MAILPART_BODY\""

echo ""

echo "--$MAILPART_BODY"

echo "Content-Type: text/plain; charset=ISO-8859-1"

echo "You need to enable HTML option for email"

echo "--$MAILPART_BODY"

# echo "Content-Type: text/html; charset=ISO-8859-1"

echo "Content-Type: text/html; charset=UTF-8"

echo "Content-transfer-encoding: us-ascii"

echo "Content-Disposition: inline"

cat $BODY

# echo "--$MAILPART_BODY--"

echo "--$MAILPART"

echo 'Content-Type: image/jpeg; name="'$(basename $ATTACH)'"'

echo "Content-Transfer-Encoding: uuencode"

echo 'Content-Disposition: attachment; filename="'$(basename $ATTACH)'"'

echo ""

echo "--$MAILPART"

echo 'Content-Type: image/jpeg; name="'$(basename $ATTACH1)'"'

echo "Content-Transfer-Encoding: uuencode"

echo 'Content-Disposition: attachment; filename="'$(basename $ATTACH1)'"'

echo ""



(uuencode $ATTACH $(basename $ATTACH) && uuencode $ATTACH1 $(basename $ATTACH1))

echo "--$MAILPART--"

) > catout.out

cat catout.out | /usr/sbin/sendmail $MAILTO

*** In my testcid.html ***

HTML Code:





</span>NOTIFICATION<span style="color:#000080">





   "cid:headerLOGO.jpg" alt=headerLogo />

RE: xxxxx

  abcdefghijlsfdklslslsls


     asdfewrsafsdfdsfs


  Thank You.

  L

"cid:footerLOGO.jpg" alt=footerLogo/>

Below are the actual email that I received when I ran the bash script as
shown:

receivedemail.jpg

Image below should supposedly showed up in the footer location -

footerLogo.jpg

Do really appreciate your help for anyone could help me to investigate the scripts to make it work as expected.

Thanks.

Junix

Attached Images

received_email.jpg (54.7 KB)
receivedemail.jpg (30.6 KB)
footerLogo.jpg (17.2 KB)

calculator

sam12 — Sat, 04 May 2013 02:06:41 GMT

Hi,

I need to make sure my code is clean and in right format and acceptable by a coder. This is a simple calculator with all 4 operators. Did I do this right? Is there a better shorter way?
I'm new to coding, Did I follow good coding format with spaces?

Thanks.
_____________________________

#!/bin/bash
timeout=1

minus="1. Minus ( - )"
plus="2. Plus ( + )"
divide="3. Division ( / )"
multiply="4. Multipication ( * )"
quit="5. Quit"

function calc ()
{
clear
while true; do
read -p "Val1: " num1
if [[ $num1 =~ ^-?[0-9]+$ ]]; then
break
else
echo "wrong"
sleep $timeout
clear
fi
done

while [[ $REPLY != 0 ]]; do
clear
echo "Val1:" $num1
cat <<- _EOF_

Operator:

$minus
$plus
$divide
$multiply
$quit

_EOF_
read -p "Enter Selection [1-5] > "
echo

if [[ $REPLY =~ ^[1-4]$ ]]; then
if [[ $REPLY == 1 ]]; then
op=-
break
fi
if [[ $REPLY == 2 ]]; then
op=+
break
fi
if [[ $REPLY == 3 ]]; then
op=/
break
fi
if [[ $REPLY == 4 ]]; then
op=*
break
fi

if [[ $REPLY == 5 ]]; then
echo "Bye"
sleep $timeout
echo " "
exit 0
fi

else

echo "Not a valid selection"
sleep $timeout
fi
done
while true; do
clear
echo "Val1: "$num1
cat <<- _EOF_

Operator:

$minus
$plus
$divide
$multiply
$quit

_EOF_

read -p "Val2: " num2
if [[ $num2 =~ ^-?[0-9]+$ ]]; then
break
else
echo "wrong"
sleep $timeout
clear
fi
done

total=$(($num1 $op $num2))
clear
echo "Val1: "$num1
cat <<- _EOF_

Operator:

$minus
$plus
$divide
$multiply
$quit

_EOF_

echo "Val2: "$num2
echo " "
echo "Your operation is -> $num1 $op $num2 = $total"
echo
sleep 20
again
}

function again ()
{
while [[ $REPLY != 0 ]]; do
clear
echo
echo "Your operation is -> $num1 $op $num2 = $total"
echo

read -p "Start Again? [y-n]: "

if [[ $REPLY == "y" ]]; then
calc
break
fi
if [[ $REPLY == "n" ]]; then
echo "Goodbye"
sleep $timeout
echo " "
exit 0

else
echo " "
echo "Not a valid selection"
sleep $timeout
fi
done
}

calc

Bash Script add, delete users help!

vaguelines — Wed, 01 May 2013 07:30:51 GMT

i am currently trying to create a script which presents any particular person with a menu when running this particular bash script. On the menu i have allowed three options (1. Add user, 2. Delete user and 3.Quit). In relation to the add user option once selected there should be 2 options which allow the user to manually input details for a new user or add multiple users via a text file. I have been able to create the menus/options described above although i have been unable to create the script/body of the tasks for the add user manually and many users via txt file aswell as delete user.Any advice or correcting to my code would be much appreciated thanks a lot

Here is my script as of now :

Code:

#!/bin/bash

Code:

    clear

    echo "########## MENU ############\n"

    options=("add_user" "delete_user" "exit")

    select opt in "${options[@]}"

    do

        case $opt in

                "add_user")

                        clear

                while [ 1 ]

    do

      clear

      echo "1. Add user manually"

      echo "2. Add user via TXT file"

      read -p "Enter your choice" ch

      case $ch in 

          1)

            read -p "Enter user name : " useradd

           read -p "Enter user password:" passwd

                echo -e "Successfully added the user"

                ;;

        2)

       if [ $(id -u) -eq 0 ]; then

      for row in `more $1`

      do

      username=${row%:*}

      password=${row#*:}





     egrep "^$username" /etc/passwd >/dev/null

    

     if [ $? -eq 0 ]; then

        echo "$username exists!"

        exit 1

     else

        pass=$(perl -e 'print crypt($ARGV[0], "password")' $password)

        useradd -m -p $pass $username

        [ $? -eq 0 ] && echo "User has been added to system!" || echo "Failed to add a 

        user!"    

    fi

    done

        else

            echo "Only root may add a user to the system"

            exit 2

    fi    

        esac  

        done

                ;;

                "delete_user")

                        read -p "Enter a User name to delete "UNAME

                        passwd

                        userdel $UNAME

                        echo "User $UNAME has been deleted"                        





                        ;;

                "exit")

                        break

                        ;;

        

                esac

        done

Search and move with directory structure maintend.

rahuljanghel — Tue, 30 Apr 2013 17:04:23 GMT

Hi Friends,

I am looking for a simple bash command / script which checks source location for 30 days old file and moves to destination maintaining the same directory structure as source had. Its easy to find 30 days old file, but facing difficulty with maintained same directory structure as sources. Pls suggest.

Regards,
Rahul Janghel.