Thread: Help with execvp function in C program !

I knew that execvp exec a child process with its argument list.

Code:

int main ()
{
  /* The argument list to pass to the “ls” command. */
  char* arg_list[] = {
     “ls”,     /* argv[0], the name of the program. */
     “-l”,
     “/”,
     NULL      /* The argument list must end with a NULL.  */
  };
pid_t child_pid;
/* Duplicate this process. */
child_pid = fork ();
if (child_pid != 0)
  /* This is the parent process. */
  return child_pid;
else {
  /* Now execute PROGRAM, searching for it in the path. */
  execvp (ls, arg_list);

  fprintf (stderr, “an error occurred in execvp\n”);
  abort ();

  printf (“done with main program\n”);
  return 0;
}

But if I want to execute my shell or php script in exec

Code:

phpPATH=/usr/local/bin/php
scriptPATH=/usr/local/apache/htdocs/myweb/myscript.php

I've failed with

Code:

char* arg_list[] = {
     “phpPATH”,
     “scriptPATH”,
     “scriptArgument”,
     NULL      /* The argument list must end with a NULL.  */
  };
----------------
execvp(phpPATH,arg_list)

How can I use execvp with my own script ?
Thanks in advanced !

Is it Linux or any other UNIX box? Also, do you get any specific error code or message? For further debugging try

PHP Code:

strace ./a.out
strace ./yourapp 


Here is my test.c

PHP Code:

#include <sys/types.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>

int main()
{
   pid_t pid;
   char *const parmList[] = 
   {"/usr/bin/php", "/tmp/test.php", NULL};

   if ((pid = fork()) == -1)
      perror("fork() error");
   else if (pid == 0) {
      execvp("/usr/bin/php", parmList);
      printf("Return not expected. Must be an execvp() error.\n");
   }
} 


Here is my test.php

PHP Code:

#!/usr/bin/php
<?php
    echo "Test\n";
?>

Output:

Code:

./test

Test

thank you so much. IT's working !